Solve 41/11+7/11+11/10

$$4 \frac { 1 } { 11 } + \frac { 7 } { 11 } + 1 \frac { 1 } { 10 }$$

Evaluate

$$\frac{641}{110}\approx 5.827272727$$

Solution Steps

Multiply 4 and 11 to get 44.

$$\frac{44+1}{11}+\frac{7}{11}+\frac{1\times 10+1}{10}$$

Add 44 and 1 to get 45.

$$\frac{45}{11}+\frac{7}{11}+\frac{1\times 10+1}{10}$$

Since \frac{45}{11} and \frac{7}{11} have the same denominator, add them by adding their numerators.

$$\frac{45+7}{11}+\frac{1\times 10+1}{10}$$

Add 45 and 7 to get 52.

$$\frac{52}{11}+\frac{1\times 10+1}{10}$$

Multiply 1 and 10 to get 10.

$$\frac{52}{11}+\frac{10+1}{10}$$

Add 10 and 1 to get 11.

$$\frac{52}{11}+\frac{11}{10}$$

Least common multiple of 11 and 10 is 110. Convert \frac{52}{11} and \frac{11}{10} to fractions with denominator 110.

$$\frac{520}{110}+\frac{121}{110}$$

Since \frac{520}{110} and \frac{121}{110} have the same denominator, add them by adding their numerators.

$$\frac{520+121}{110}$$

Add 520 and 121 to get 641.

$$\frac{641}{110}$$

Factor

$$\frac{641}{2 \cdot 5 \cdot 11} = 5\frac{91}{110} = 5.827272727272727$$