Solve 41/10-93/5=

$$4 \frac { 1 } { 10 } - 9 \frac { 3 } { 5 } =$$

Evaluate

$$-\frac{11}{2}=-5.5$$

Solution Steps

Multiply 4 and 10 to get 40.

$$\frac{40+1}{10}-\frac{9\times 5+3}{5}$$

Add 40 and 1 to get 41.

$$\frac{41}{10}-\frac{9\times 5+3}{5}$$

Multiply 9 and 5 to get 45.

$$\frac{41}{10}-\frac{45+3}{5}$$

Add 45 and 3 to get 48.

$$\frac{41}{10}-\frac{48}{5}$$

Least common multiple of 10 and 5 is 10. Convert \frac{41}{10} and \frac{48}{5} to fractions with denominator 10.

$$\frac{41}{10}-\frac{96}{10}$$

Since \frac{41}{10} and \frac{96}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{41-96}{10}$$

Subtract 96 from 41 to get -55.

$$\frac{-55}{10}$$

Reduce the fraction \frac{-55}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{11}{2}$$

Factor

$$-\frac{11}{2} = -5\frac{1}{2} = -5.5$$