Solve for f
f=\frac{7e^{-\frac{1}{x^{2}}}}{4x}
x\neq 0
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4fx=7e^{-\frac{1}{x^{2}}}
Reorder the terms.
4xf=7e^{-\frac{1}{x^{2}}}
The equation is in standard form.
\frac{4xf}{4x}=\frac{7e^{-\frac{1}{x^{2}}}}{4x}
Divide both sides by 4x.
f=\frac{7e^{-\frac{1}{x^{2}}}}{4x}
Dividing by 4x undoes the multiplication by 4x.
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