Solve 4*3^6-11*27^2+7*9^3

$$4 \cdot 3 ^ { 6 } - 11 \cdot 27 ^ { 2 } + 7 \cdot 9 ^ { 3 }$$

Evaluate

$$0$$

Solution Steps

Calculate 3 to the power of 6 and get 729.

$$4\times 729-11\times 27^{2}+7\times 9^{3}$$

Multiply 4 and 729 to get 2916.

$$2916-11\times 27^{2}+7\times 9^{3}$$

Calculate 27 to the power of 2 and get 729.

$$2916-11\times 729+7\times 9^{3}$$

Multiply 11 and 729 to get 8019.

$$2916-8019+7\times 9^{3}$$

Subtract 8019 from 2916 to get -5103.

$$-5103+7\times 9^{3}$$

Calculate 9 to the power of 3 and get 729.

$$-5103+7\times 729$$

Multiply 7 and 729 to get 5103.

$$-5103+5103$$

Add -5103 and 5103 to get 0.

$$0$$

Factor

$$0$$