Solve 4*(-5)^3+(-4)^3-(-2018)^0

$$4 \cdot ( - 5 ) ^ { 3 } + ( - 4 ) ^ { 3 } - ( - 2018 ) ^ { 0 }$$

Evaluate

$$-565$$

Solution Steps

Calculate -5 to the power of 3 and get -125.

$$4\left(-125\right)+\left(-4\right)^{3}-\left(-2018\right)^{0}$$

Multiply 4 and -125 to get -500.

$$-500+\left(-4\right)^{3}-\left(-2018\right)^{0}$$

Calculate -4 to the power of 3 and get -64.

$$-500-64-\left(-2018\right)^{0}$$

Subtract 64 from -500 to get -564.

$$-564-\left(-2018\right)^{0}$$

Calculate -2018 to the power of 0 and get 1.

$$-564-1$$

Subtract 1 from -564 to get -565.

$$-565$$

Factor

$$-565$$