Solve 4*3-9-4*3-12/3=3-3-3/3

$$4 \cdot 3-9- \frac{ 4 \cdot 3-12 }{ 3 } = 3- \frac{ 3-3 }{ 3 }$$

Verify

Solution Steps

Multiply both sides of the equation by 3.

$$12\times 3-27-\left(4\times 3-12\right)=9-\left(3-3\right)$$

Multiply 12 and 3 to get 36.

$$36-27-\left(4\times 3-12\right)=9-\left(3-3\right)$$

Subtract 27 from 36 to get 9.

$$9-\left(4\times 3-12\right)=9-\left(3-3\right)$$

Multiply 4 and 3 to get 12.

$$9-\left(12-12\right)=9-\left(3-3\right)$$

Subtract 12 from 12 to get 0.

$$9+0=9-\left(3-3\right)$$

Add 9 and 0 to get 9.

$$9=9-\left(3-3\right)$$

Subtract 3 from 3 to get 0.

$$9=9+0$$

Add 9 and 0 to get 9.

$$9=9$$

Compare 9 and 9.

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