Solve 4{3(t+s)-2[1-(t+1)]}

$$4 \{ 3 ( t + s ) - 2 [ 1 - ( t + 1 ) ] \}$$

Evaluate

$$12s+20t$$

Solution Steps

Use the distributive property to multiply 3 by t+s.

$$4\left(3t+3s-2\left(1-\left(t+1\right)\right)\right)$$

To find the opposite of t+1, find the opposite of each term.

$$4\left(3t+3s-2\left(1-t-1\right)\right)$$

Subtract 1 from 1 to get 0.

$$4\left(3t+3s-2\left(-1\right)t\right)$$

Multiply 2 and -1 to get -2.

$$4\left(3t+3s-\left(-2t\right)\right)$$

The opposite of -2t is 2t.

$$4\left(3t+3s+2t\right)$$

Use the distributive property to multiply 4 by 3t+3s+2t.

$$12t+12s+8t$$

Combine 12t and 8t to get 20t.

$$20t+12s$$

Expand

$$12s+20t$$

Solution Steps

Use the distributive property to multiply 3 by t+s.

$$4\left(3t+3s-2\left(1-\left(t+1\right)\right)\right)$$

To find the opposite of t+1, find the opposite of each term.

$$4\left(3t+3s-2\left(1-t-1\right)\right)$$

Subtract 1 from 1 to get 0.

$$4\left(3t+3s-2\left(-1\right)t\right)$$

Multiply 2 and -1 to get -2.

$$4\left(3t+3s-\left(-2t\right)\right)$$

The opposite of -2t is 2t.

$$4\left(3t+3s+2t\right)$$

Use the distributive property to multiply 4 by 3t+3s+2t.

$$12t+12s+8t$$

Combine 12t and 8t to get 20t.

$$20t+12s$$