Solve 4{2-[3(c+1)]}=-2c

$$4 \{ 2 - [ 3 ( c + 1 ) ] \} = - 2 c$$

Solve for c

$$c=-\frac{2}{5}=-0.4$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by c+1.

$$4\left(2-3c-3\right)=-2c$$

Subtract 3 from 2 to get -1.

$$4\left(-1-3c\right)=-2c$$

Use the distributive property to multiply 4 by -1-3c.

$$-4-12c=-2c$$

Add 2c to both sides.

$$-4-12c+2c=0$$

Combine -12c and 2c to get -10c.

$$-4-10c=0$$

Add 4 to both sides. Anything plus zero gives itself.

$$-10c=4$$

Divide both sides by -10.

$$c=\frac{4}{-10}$$

Reduce the fraction \frac{4}{-10} to lowest terms by extracting and canceling out 2.

$$c=-\frac{2}{5}$$