Solve 4^x-y^2uy=-x+2

$$4 ^ { x - y ^ { 2 } } u y = - x + 2$$

Solve for u (complex solution)

$$\left\{\begin{matrix}u=-\frac{x-2}{y\times 4^{x-y^{2}}}\text{, }&y\neq 0\\u\in \mathrm{C}\text{, }&x=2\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$y\times 4^{x-y^{2}}u=2-x$$

Divide both sides by 4^{x-y^{2}}y.

$$\frac{y\times 4^{x-y^{2}}u}{y\times 4^{x-y^{2}}}=\frac{2-x}{y\times 4^{x-y^{2}}}$$

Dividing by 4^{x-y^{2}}y undoes the multiplication by 4^{x-y^{2}}y.

$$u=\frac{2-x}{y\times 4^{x-y^{2}}}$$

Solve for u

$$\left\{\begin{matrix}u=-\frac{\left(x-2\right)\times 2^{2\left(y^{2}-x\right)}}{y}\text{, }&y\neq 0\\u\in \mathrm{R}\text{, }&x=2\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$y\times 4^{x-y^{2}}u=2-x$$

Divide both sides by 4^{x-y^{2}}y.

$$\frac{y\times 4^{x-y^{2}}u}{y\times 4^{x-y^{2}}}=\frac{2-x}{y\times 4^{x-y^{2}}}$$

Dividing by 4^{x-y^{2}}y undoes the multiplication by 4^{x-y^{2}}y.

$$u=\frac{2-x}{y\times 4^{x-y^{2}}}$$