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4^{6y}=9
Use the rules of exponents and logarithms to solve the equation.
\log(4^{6y})=\log(9)
Take the logarithm of both sides of the equation.
6y\log(4)=\log(9)
The logarithm of a number raised to a power is the power times the logarithm of the number.
6y=\frac{\log(9)}{\log(4)}
Divide both sides by \log(4).
6y=\log_{4}\left(9\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
y=\frac{\log_{2}\left(3\right)}{6}
Divide both sides by 6.