Solve 4^3x5^0+(-3^4)-7^0

$$4 ^ { 3 } x 5 ^ { 0 } + ( - 3 ^ { 4 } ) - 7 ^ { 0 }$$

Evaluate

$$64x-82$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$64x\times 5^{0}-3^{4}-7^{0}$$

Calculate 5 to the power of 0 and get 1.

$$64x\times 1-3^{4}-7^{0}$$

Multiply 64 and 1 to get 64.

$$64x-3^{4}-7^{0}$$

Calculate 3 to the power of 4 and get 81.

$$64x-81-7^{0}$$

Calculate 7 to the power of 0 and get 1.

$$64x-81-1$$

Subtract 1 from -81 to get -82.

$$64x-82$$

Factor

$$2\left(32x-41\right)$$

Solution Steps

Multiply and combine like terms.

$$64x-82$$

Factor out 2.

$$2\left(32x-41\right)$$