Solve 4^3-16div2+(25*6-27)-sqrt[3]{-64}

$$4 ^ { 3 } - 16 \div 2 + ( 25 \times 6 - 27 ) - \sqrt[ 3 ] { - 64 }$$

Evaluate

$$183$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$64-\frac{16}{2}+25\times 6-27-\sqrt[3]{-64}$$

Divide 16 by 2 to get 8.

$$64-8+25\times 6-27-\sqrt[3]{-64}$$

Subtract 8 from 64 to get 56.

$$56+25\times 6-27-\sqrt[3]{-64}$$

Multiply 25 and 6 to get 150.

$$56+150-27-\sqrt[3]{-64}$$

Add 56 and 150 to get 206.

$$206-27-\sqrt[3]{-64}$$

Subtract 27 from 206 to get 179.

$$179-\sqrt[3]{-64}$$

Calculate \sqrt[3]{-64} and get -4.

$$179-\left(-4\right)$$

The opposite of -4 is 4.

$$179+4$$

Add 179 and 4 to get 183.

$$183$$

Factor

$$3\times 61$$