Solve 4^3:(1/4)^-2+(1/2)^-4:2^3=

$$4 ^ { 3 } : ( \frac { 1 } { 4 } ) ^ { - 2 } + ( \frac { 1 } { 2 } ) ^ { - 4 } : 2 ^ { 3 } =$$

Evaluate

$$6$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$\frac{64}{\left(\frac{1}{4}\right)^{-2}}+\frac{\left(\frac{1}{2}\right)^{-4}}{2^{3}}$$

Calculate \frac{1}{4} to the power of -2 and get 16.

$$\frac{64}{16}+\frac{\left(\frac{1}{2}\right)^{-4}}{2^{3}}$$

Divide 64 by 16 to get 4.

$$4+\frac{\left(\frac{1}{2}\right)^{-4}}{2^{3}}$$

Calculate \frac{1}{2} to the power of -4 and get 16.

$$4+\frac{16}{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$4+\frac{16}{8}$$

Divide 16 by 8 to get 2.

$$4+2$$

Add 4 and 2 to get 6.

$$6$$

Factor

$$2\times 3$$