Solve 4^3+4^0+4^-1+4^-2

$$4 ^ { 3 } + 4 ^ { 0 } + 4 ^ { - 1 } + 4 ^ { - 2 }$$

Evaluate

$$\frac{1045}{16}=65.3125$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$64+4^{0}+4^{-1}+4^{-2}$$

Calculate 4 to the power of 0 and get 1.

$$64+1+4^{-1}+4^{-2}$$

Add 64 and 1 to get 65.

$$65+4^{-1}+4^{-2}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$65+\frac{1}{4}+4^{-2}$$

Add 65 and \frac{1}{4} to get \frac{261}{4}.

$$\frac{261}{4}+4^{-2}$$

Calculate 4 to the power of -2 and get \frac{1}{16}.

$$\frac{261}{4}+\frac{1}{16}$$

Add \frac{261}{4} and \frac{1}{16} to get \frac{1045}{16}.

$$\frac{1045}{16}$$

Factor

$$\frac{5 \cdot 11 \cdot 19}{2 ^ {4}} = 65\frac{5}{16} = 65.3125$$