Solve 4^{3}+3*7^{2}*21-2^4*3+3^3*6:18-2^5+3^0

$$4 ^ { 3 } + 3 \times 7 ^ { 2 } \cdot 21 - 2 ^ { 4 } \times 3 + 3 ^ { 3 } \times 6 : 18 - 2 ^ { 5 } + 3 ^ { 0 }$$

Evaluate

$$3081$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$64+3\times 7^{2}\times 21-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Calculate 7 to the power of 2 and get 49.

$$64+3\times 49\times 21-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Multiply 3 and 49 to get 147.

$$64+147\times 21-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Multiply 147 and 21 to get 3087.

$$64+3087-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Add 64 and 3087 to get 3151.

$$3151-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Calculate 2 to the power of 4 and get 16.

$$3151-16\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Multiply 16 and 3 to get 48.

$$3151-48+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Subtract 48 from 3151 to get 3103.

$$3103+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Calculate 3 to the power of 3 and get 27.

$$3103+\frac{27\times 6}{18}-2^{5}+3^{0}$$

Multiply 27 and 6 to get 162.

$$3103+\frac{162}{18}-2^{5}+3^{0}$$

Divide 162 by 18 to get 9.

$$3103+9-2^{5}+3^{0}$$

Add 3103 and 9 to get 3112.

$$3112-2^{5}+3^{0}$$

Calculate 2 to the power of 5 and get 32.

$$3112-32+3^{0}$$

Subtract 32 from 3112 to get 3080.

$$3080+3^{0}$$

Calculate 3 to the power of 0 and get 1.

$$3080+1$$

Add 3080 and 1 to get 3081.

$$3081$$

Factor

$$3\times 13\times 79$$