Solve 4^2*y=7/(3x)^-2

$$4 ^ { 2 } \cdot y = \frac { 7 } { ( 3 x ) ^ { - 2 } }$$

Solve for y

$$y=\frac{63x^{2}}{16}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Calculate 4 to the power of 2 and get 16.

$$16y=\frac{7}{\left(3x\right)^{-2}}$$

Expand \left(3x\right)^{-2}.

$$16y=\frac{7}{3^{-2}x^{-2}}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$16y=\frac{7}{\frac{1}{9}x^{-2}}$$

The equation is in standard form.

$$16y=63x^{2}$$

Divide both sides by 16.

$$\frac{16y}{16}=\frac{63x^{2}}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$y=\frac{63x^{2}}{16}$$

Solve for x (complex solution)

$$x=-\frac{4\sqrt{7y}}{21}$$

$$x=\frac{4\sqrt{7y}}{21}\text{, }y\neq 0$$

Solve for x

$$x=\frac{4\sqrt{7y}}{21}$$

$$x=-\frac{4\sqrt{7y}}{21}\text{, }y>0$$