Solve 4^2+2div(6*6)-1

$$4 ^ { 2 } + 2 \div ( 6 \times 6 ) - 1$$

Evaluate

$$\frac{271}{18}\approx 15.055555556$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16+\frac{2}{6\times 6}-1$$

Multiply 6 and 6 to get 36.

$$16+\frac{2}{36}-1$$

Reduce the fraction \frac{2}{36} to lowest terms by extracting and canceling out 2.

$$16+\frac{1}{18}-1$$

Convert 16 to fraction \frac{288}{18}.

$$\frac{288}{18}+\frac{1}{18}-1$$

Since \frac{288}{18} and \frac{1}{18} have the same denominator, add them by adding their numerators.

$$\frac{288+1}{18}-1$$

Add 288 and 1 to get 289.

$$\frac{289}{18}-1$$

Convert 1 to fraction \frac{18}{18}.

$$\frac{289}{18}-\frac{18}{18}$$

Since \frac{289}{18} and \frac{18}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{289-18}{18}$$

Subtract 18 from 289 to get 271.

$$\frac{271}{18}$$

Factor

$$\frac{271}{2 \cdot 3 ^ {2}} = 15\frac{1}{18} = 15.055555555555555$$