Solve 4^2+(4)(-3)-3(4/-3)^2

$$4 ^ { 2 } + ( 4 ) ( - 3 ) - 3 ( \frac { 4 } { - 3 } ) ^ { 2 }$$

Evaluate

$$-\frac{4}{3}\approx -1.333333333$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16+4\left(-3\right)-3\times \left(\frac{4}{-3}\right)^{2}$$

Multiply 4 and -3 to get -12.

$$16-12-3\times \left(\frac{4}{-3}\right)^{2}$$

Subtract 12 from 16 to get 4.

$$4-3\times \left(\frac{4}{-3}\right)^{2}$$

Fraction \frac{4}{-3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$4-3\left(-\frac{4}{3}\right)^{2}$$

Calculate -\frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$4-3\times \frac{16}{9}$$

Multiply 3 and \frac{16}{9} to get \frac{16}{3}.

$$4-\frac{16}{3}$$

Subtract \frac{16}{3} from 4 to get -\frac{4}{3}.

$$-\frac{4}{3}$$

Factor

$$-\frac{4}{3} = -1\frac{1}{3} = -1.3333333333333333$$