Solve 4^2+sqrt[3]{6}div7

$$4 ^ { 2 } + \sqrt[ 3 ] { 6 } \div 7$$

Evaluate

$$\frac{\sqrt[3]{6}}{7}+16\approx 16.259588656$$

Short Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16+\frac{\sqrt[3]{6}}{7}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 16 times \frac{7}{7}.

$$\frac{16\times 7}{7}+\frac{\sqrt[3]{6}}{7}$$

Since \frac{16\times 7}{7} and \frac{\sqrt[3]{6}}{7} have the same denominator, add them by adding their numerators.

$$\frac{16\times 7+\sqrt[3]{6}}{7}$$

Do the multiplications in 16\times 7+\sqrt[3]{6}.

$$\frac{112+\sqrt[3]{6}}{7}$$

Factor

$$\frac{\sqrt[3]{6} + 112}{7} = 16.259588656118876$$