Solve 4[2x+5(3-2x)-12]=5(x-1)+3(x+1)+18

$$4 [ 2 x + 5 ( 3 - 2 x ) - 12 ] = 5 ( x - 1 ) + 3 ( x + 1 ) + 18$$

Solve for x

$$x=-\frac{1}{10}=-0.1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by 3-2x.

$$4\left(2x+15-10x-12\right)=5\left(x-1\right)+3\left(x+1\right)+18$$

Combine 2x and -10x to get -8x.

$$4\left(-8x+15-12\right)=5\left(x-1\right)+3\left(x+1\right)+18$$

Subtract 12 from 15 to get 3.

$$4\left(-8x+3\right)=5\left(x-1\right)+3\left(x+1\right)+18$$

Use the distributive property to multiply 4 by -8x+3.

$$-32x+12=5\left(x-1\right)+3\left(x+1\right)+18$$

Use the distributive property to multiply 5 by x-1.

$$-32x+12=5x-5+3\left(x+1\right)+18$$

Use the distributive property to multiply 3 by x+1.

$$-32x+12=5x-5+3x+3+18$$

Combine 5x and 3x to get 8x.

$$-32x+12=8x-5+3+18$$

Add -5 and 3 to get -2.

$$-32x+12=8x-2+18$$

Add -2 and 18 to get 16.

$$-32x+12=8x+16$$

Subtract 8x from both sides.

$$-32x+12-8x=16$$

Combine -32x and -8x to get -40x.

$$-40x+12=16$$

Subtract 12 from both sides.

$$-40x=16-12$$

Subtract 12 from 16 to get 4.

$$-40x=4$$

Divide both sides by -40.

$$x=\frac{4}{-40}$$

Reduce the fraction \frac{4}{-40} to lowest terms by extracting and canceling out 4.

$$x=-\frac{1}{10}$$