Solve 4=c(12a+17b)

$$4 = c ( 12 a + 17 b )$$

Solve for a

$$a=-\frac{17b}{12}+\frac{1}{3c}$$

$$c\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply c by 12a+17b.

$$4=12ca+17cb$$

Swap sides so that all variable terms are on the left hand side.

$$12ca+17cb=4$$

Subtract 17cb from both sides.

$$12ca=4-17cb$$

The equation is in standard form.

$$12ca=4-17bc$$

Divide both sides by 12c.

$$\frac{12ca}{12c}=\frac{4-17bc}{12c}$$

Dividing by 12c undoes the multiplication by 12c.

$$a=\frac{4-17bc}{12c}$$

Divide 4-17cb by 12c.

$$a=-\frac{17b}{12}+\frac{1}{3c}$$

Solve for b

$$b=-\frac{12a}{17}+\frac{4}{17c}$$

$$c\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply c by 12a+17b.

$$4=12ca+17cb$$

Swap sides so that all variable terms are on the left hand side.

$$12ca+17cb=4$$

Subtract 12ca from both sides.

$$17cb=4-12ca$$

The equation is in standard form.

$$17cb=4-12ac$$

Divide both sides by 17c.

$$\frac{17cb}{17c}=\frac{4-12ac}{17c}$$

Dividing by 17c undoes the multiplication by 17c.

$$b=\frac{4-12ac}{17c}$$

Divide 4-12ca by 17c.

$$b=-\frac{12a}{17}+\frac{4}{17c}$$