Solve 4=2*6-(3+2*3)+[5(3+2)-17]

$$4 = 2 \times 6 - ( 3 + 2 \times 3 ) + [ 5 ( 3 + 2 ) - 17 ]$$

Verify

Solution Steps

Multiply 2 and 6 to get 12.

$$4=12-\left(3+2\times 3\right)+5\left(3+2\right)-17$$

Multiply 2 and 3 to get 6.

$$4=12-\left(3+6\right)+5\left(3+2\right)-17$$

Add 3 and 6 to get 9.

$$4=12-9+5\left(3+2\right)-17$$

Subtract 9 from 12 to get 3.

$$4=3+5\left(3+2\right)-17$$

Add 3 and 2 to get 5.

$$4=3+5\times 5-17$$

Multiply 5 and 5 to get 25.

$$4=3+25-17$$

Add 3 and 25 to get 28.

$$4=28-17$$

Subtract 17 from 28 to get 11.

$$4=11$$

Compare 4 and 11.

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