Solve for b
b=\frac{3x}{7}+11
Solve for x
x=\frac{7\left(b-11\right)}{3}
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-\frac{3}{7}x-7+b=4
Swap sides so that all variable terms are on the left hand side.
-7+b=4+\frac{3}{7}x
Add \frac{3}{7}x to both sides.
b=4+\frac{3}{7}x+7
Add 7 to both sides.
b=11+\frac{3}{7}x
Add 4 and 7 to get 11.
-\frac{3}{7}x-7+b=4
Swap sides so that all variable terms are on the left hand side.
-\frac{3}{7}x+b=4+7
Add 7 to both sides.
-\frac{3}{7}x+b=11
Add 4 and 7 to get 11.
-\frac{3}{7}x=11-b
Subtract b from both sides.
\frac{-\frac{3}{7}x}{-\frac{3}{7}}=\frac{11-b}{-\frac{3}{7}}
Divide both sides of the equation by -\frac{3}{7}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{11-b}{-\frac{3}{7}}
Dividing by -\frac{3}{7} undoes the multiplication by -\frac{3}{7}.
x=\frac{7b-77}{3}
Divide 11-b by -\frac{3}{7} by multiplying 11-b by the reciprocal of -\frac{3}{7}.
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