Solve 4=(x^2-ax+bx)-ab

$$4 = ( x ^ { 2 } - a x + b x ) - a b$$

Solve for a

$$a=\frac{x^{2}+bx-4}{x+b}$$

$$x\neq -b$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$x^{2}-ax+bx-ab=4$$

Subtract x^{2} from both sides.

$$-ax+bx-ab=4-x^{2}$$

Subtract bx from both sides.

$$-ax-ab=4-x^{2}-bx$$

Combine all terms containing a.

$$\left(-x-b\right)a=4-x^{2}-bx$$

The equation is in standard form.

$$\left(-x-b\right)a=4-bx-x^{2}$$

Divide both sides by -x-b.

$$\frac{\left(-x-b\right)a}{-x-b}=\frac{4-bx-x^{2}}{-x-b}$$

Dividing by -x-b undoes the multiplication by -x-b.

$$a=\frac{4-bx-x^{2}}{-x-b}$$

Divide 4-x^{2}-bx by -x-b.

$$a=-\frac{4-bx-x^{2}}{x+b}$$

Solve for b

$$b=-\frac{x^{2}-ax-4}{x-a}$$

$$x\neq a$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$x^{2}-ax+bx-ab=4$$

Subtract x^{2} from both sides.

$$-ax+bx-ab=4-x^{2}$$

Add ax to both sides.

$$bx-ab=4-x^{2}+ax$$

Combine all terms containing b.

$$\left(x-a\right)b=4-x^{2}+ax$$

The equation is in standard form.

$$\left(x-a\right)b=4+ax-x^{2}$$

Divide both sides by x-a.

$$\frac{\left(x-a\right)b}{x-a}=\frac{4+ax-x^{2}}{x-a}$$

Dividing by x-a undoes the multiplication by x-a.

$$b=\frac{4+ax-x^{2}}{x-a}$$