Solve 4=sqrt{26-5x+x}

$$4 = \sqrt { 26 - 5 x + x }$$

Solve for x

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Steps for Solving Radical Equations

Combine -5x and x to get -4x.

$$4=\sqrt{26-4x}$$

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{26-4x}=4$$

Square both sides of the equation.

$$-4x+26=16$$

Subtract 26 from both sides of the equation.

$$-4x+26-26=16-26$$

Subtracting 26 from itself leaves 0.

$$-4x=16-26$$

Subtract 26 from 16.

$$-4x=-10$$

Divide both sides by -4.

$$\frac{-4x}{-4}=-\frac{10}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=-\frac{10}{-4}$$

Reduce the fraction \frac{-10}{-4} to lowest terms by extracting and canceling out 2.

$$x=\frac{5}{2}$$