Solve 4:(7/9*6/5*15/28)-3=

$$4 : ( \frac { 7 } { 9 } \cdot \frac { 6 } { 5 } \cdot \frac { 15 } { 28 } ) - 3 =$$

Evaluate

$$5$$

Solution Steps

Multiply \frac{7}{9} times \frac{6}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4}{\frac{7\times 6}{9\times 5}\times \frac{15}{28}}-3$$

Do the multiplications in the fraction \frac{7\times 6}{9\times 5}.

$$\frac{4}{\frac{42}{45}\times \frac{15}{28}}-3$$

Reduce the fraction \frac{42}{45} to lowest terms by extracting and canceling out 3.

$$\frac{4}{\frac{14}{15}\times \frac{15}{28}}-3$$

Multiply \frac{14}{15} times \frac{15}{28} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4}{\frac{14\times 15}{15\times 28}}-3$$

Cancel out 15 in both numerator and denominator.

$$\frac{4}{\frac{14}{28}}-3$$

Reduce the fraction \frac{14}{28} to lowest terms by extracting and canceling out 14.

$$\frac{4}{\frac{1}{2}}-3$$

Divide 4 by \frac{1}{2} by multiplying 4 by the reciprocal of \frac{1}{2}.

$$4\times 2-3$$

Multiply 4 and 2 to get 8.

$$8-3$$

Subtract 3 from 8 to get 5.

$$5$$

Factor

$$5$$