Solve for x
x=80
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\frac{19}{20}x+4=x
Combine \frac{4}{5}x and \frac{3}{20}x to get \frac{19}{20}x.
\frac{19}{20}x+4-x=0
Subtract x from both sides.
-\frac{1}{20}x+4=0
Combine \frac{19}{20}x and -x to get -\frac{1}{20}x.
-\frac{1}{20}x=-4
Subtract 4 from both sides. Anything subtracted from zero gives its negation.
x=-4\left(-20\right)
Multiply both sides by -20, the reciprocal of -\frac{1}{20}.
x=80
Multiply -4 and -20 to get 80.
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