Solve 4+y=1/3(x+9)

$$4 + y = \frac { 1 } { 3 } ( x + 9 )$$

Solve for x

$$x=3\left(y+1\right)$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{3} by x+9.

$$4+y=\frac{1}{3}x+3$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+3=4+y$$

Subtract 3 from both sides.

$$\frac{1}{3}x=4+y-3$$

Subtract 3 from 4 to get 1.

$$\frac{1}{3}x=1+y$$

The equation is in standard form.

$$\frac{1}{3}x=y+1$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y+1}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{y+1}{\frac{1}{3}}$$

Divide 1+y by \frac{1}{3} by multiplying 1+y by the reciprocal of \frac{1}{3}.

$$x=3y+3$$

Solve for y

$$y=\frac{x-3}{3}$$

Solution Steps

Use the distributive property to multiply \frac{1}{3} by x+9.

$$4+y=\frac{1}{3}x+3$$

Subtract 4 from both sides.

$$y=\frac{1}{3}x+3-4$$

Subtract 4 from 3 to get -1.

$$y=\frac{1}{3}x-1$$