Solve 4+x^2-1=(x-1)^2

$$4 + x ^ { 2 } - 1 = ( x - 1 ) ^ { 2 }$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Subtract 1 from 4 to get 3.

$$3+x^{2}=\left(x-1\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.

$$3+x^{2}=x^{2}-2x+1$$

Subtract x^{2} from both sides.

$$3+x^{2}-x^{2}=-2x+1$$

Combine x^{2} and -x^{2} to get 0.

$$3=-2x+1$$

Swap sides so that all variable terms are on the left hand side.

$$-2x+1=3$$

Subtract 1 from both sides.

$$-2x=3-1$$

Subtract 1 from 3 to get 2.

$$-2x=2$$

Divide both sides by -2.

$$x=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$x=-1$$