Solve 4+3(4^2-2*4*6+6^2)

$$4 + 3 ( 4 ^ { 2 } - 2 \times 4 \times 6 + 6 ^ { 2 } )$$

Evaluate

$$16$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$4+3\left(16-2\times 4\times 6+6^{2}\right)$$

Multiply 2 and 4 to get 8.

$$4+3\left(16-8\times 6+6^{2}\right)$$

Multiply 8 and 6 to get 48.

$$4+3\left(16-48+6^{2}\right)$$

Subtract 48 from 16 to get -32.

$$4+3\left(-32+6^{2}\right)$$

Calculate 6 to the power of 2 and get 36.

$$4+3\left(-32+36\right)$$

Add -32 and 36 to get 4.

$$4+3\times 4$$

Multiply 3 and 4 to get 12.

$$4+12$$

Add 4 and 12 to get 16.

$$16$$

Factor

$$2^{4}$$