Solve for x
x=-\frac{3y}{2}+10
Solve for y
y=\frac{20-2x}{3}
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20-2x=3y
Swap sides so that all variable terms are on the left hand side.
-2x=3y-20
Subtract 20 from both sides.
\frac{-2x}{-2}=\frac{3y-20}{-2}
Divide both sides by -2.
x=\frac{3y-20}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-\frac{3y}{2}+10
Divide 3y-20 by -2.
3y=20-2x
The equation is in standard form.
\frac{3y}{3}=\frac{20-2x}{3}
Divide both sides by 3.
y=\frac{20-2x}{3}
Dividing by 3 undoes the multiplication by 3.
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