Solve for x
x=-\frac{3y}{2}+8
Solve for y
y=\frac{16-2x}{3}
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2x=16-3y
Subtract 3y from both sides.
\frac{2x}{2}=\frac{16-3y}{2}
Divide both sides by 2.
x=\frac{16-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}+8
Divide 16-3y by 2.
3y=16-2x
Subtract 2x from both sides.
\frac{3y}{3}=\frac{16-2x}{3}
Divide both sides by 3.
y=\frac{16-2x}{3}
Dividing by 3 undoes the multiplication by 3.
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