Solve 3xy-6x-6y+14=7/3

$$3xy-6x-6y+14= \frac{ 7 }{ 3 }$$

Solve for x

$$x=-\frac{35-18y}{9\left(y-2\right)}$$

$$y\neq 2$$

Steps for Solving Linear Equation

Add 6y to both sides.

$$3xy-6x+14=\frac{7}{3}+6y$$

Subtract 14 from both sides.

$$3xy-6x=\frac{7}{3}+6y-14$$

Subtract 14 from \frac{7}{3} to get -\frac{35}{3}.

$$3xy-6x=-\frac{35}{3}+6y$$

Combine all terms containing x.

$$\left(3y-6\right)x=-\frac{35}{3}+6y$$

The equation is in standard form.

$$\left(3y-6\right)x=6y-\frac{35}{3}$$

Divide both sides by 3y-6.

$$\frac{\left(3y-6\right)x}{3y-6}=\frac{6y-\frac{35}{3}}{3y-6}$$

Dividing by 3y-6 undoes the multiplication by 3y-6.

$$x=\frac{6y-\frac{35}{3}}{3y-6}$$

Divide -\frac{35}{3}+6y by 3y-6.

$$x=\frac{18y-35}{9\left(y-2\right)}$$

Solve for y

$$y=-\frac{35-18x}{9\left(x-2\right)}$$

$$x\neq 2$$

Steps for Solving Linear Equation

Add 6x to both sides.

$$3xy-6y+14=\frac{7}{3}+6x$$

Subtract 14 from both sides.

$$3xy-6y=\frac{7}{3}+6x-14$$

Subtract 14 from \frac{7}{3} to get -\frac{35}{3}.

$$3xy-6y=-\frac{35}{3}+6x$$

Combine all terms containing y.

$$\left(3x-6\right)y=-\frac{35}{3}+6x$$

The equation is in standard form.

$$\left(3x-6\right)y=6x-\frac{35}{3}$$

Divide both sides by 3x-6.

$$\frac{\left(3x-6\right)y}{3x-6}=\frac{6x-\frac{35}{3}}{3x-6}$$

Dividing by 3x-6 undoes the multiplication by 3x-6.

$$y=\frac{6x-\frac{35}{3}}{3x-6}$$

Divide -\frac{35}{3}+6x by 3x-6.

$$y=\frac{18x-35}{9\left(x-2\right)}$$