Solve for x
x=\frac{8}{3y+1}
y\neq -\frac{1}{3}
Solve for y
y=-\frac{1}{3}+\frac{8}{3x}
x\neq 0
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\left(3y+1\right)x=8
Combine all terms containing x.
\frac{\left(3y+1\right)x}{3y+1}=\frac{8}{3y+1}
Divide both sides by 3y+1.
x=\frac{8}{3y+1}
Dividing by 3y+1 undoes the multiplication by 3y+1.
3xy=8-x
Subtract x from both sides.
\frac{3xy}{3x}=\frac{8-x}{3x}
Divide both sides by 3x.
y=\frac{8-x}{3x}
Dividing by 3x undoes the multiplication by 3x.
y=-\frac{1}{3}+\frac{8}{3x}
Divide 8-x by 3x.
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