Solve for x
x=\frac{y-3}{3}
Solve for y
y=3\left(x+1\right)
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3x=-3+y
Add y to both sides.
3x=y-3
The equation is in standard form.
\frac{3x}{3}=\frac{y-3}{3}
Divide both sides by 3.
x=\frac{y-3}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{y}{3}-1
Divide -3+y by 3.
-y=-3-3x
Subtract 3x from both sides.
-y=-3x-3
The equation is in standard form.
\frac{-y}{-1}=\frac{-3x-3}{-1}
Divide both sides by -1.
y=\frac{-3x-3}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x+3
Divide -3-3x by -1.
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