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3x-8=4y
Add 4y to both sides. Anything plus zero gives itself.
3x=4y+8
Add 8 to both sides.
\frac{3x}{3}=\frac{4y+8}{3}
Divide both sides by 3.
x=\frac{4y+8}{3}
Dividing by 3 undoes the multiplication by 3.
-4y-8=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-4y=-3x+8
Add 8 to both sides.
-4y=8-3x
The equation is in standard form.
\frac{-4y}{-4}=\frac{8-3x}{-4}
Divide both sides by -4.
y=\frac{8-3x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{3x}{4}-2
Divide -3x+8 by -4.