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3x-2+5x^{2}-4x+x^{2}
Add -4 and 2 to get -2.
-x-2+5x^{2}+x^{2}
Combine 3x and -4x to get -x.
-x-2+6x^{2}
Combine 5x^{2} and x^{2} to get 6x^{2}.
6x^{2}-x-2
Multiply and combine like terms.
a+b=-1 ab=6\left(-2\right)=-12
Factor the expression by grouping. First, the expression needs to be rewritten as 6x^{2}+ax+bx-2. To find a and b, set up a system to be solved.
1,-12 2,-6 3,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -12.
1-12=-11 2-6=-4 3-4=-1
Calculate the sum for each pair.
a=-4 b=3
The solution is the pair that gives sum -1.
\left(6x^{2}-4x\right)+\left(3x-2\right)
Rewrite 6x^{2}-x-2 as \left(6x^{2}-4x\right)+\left(3x-2\right).
2x\left(3x-2\right)+3x-2
Factor out 2x in 6x^{2}-4x.
\left(3x-2\right)\left(2x+1\right)
Factor out common term 3x-2 by using distributive property.