Solve 3x-4+02x=15+12x+21

$$3x-4+02x=15+12x+21$$

Solve for x

$$x = -\frac{40}{9} = -4\frac{4}{9} \approx -4.444444444$$

Steps for Solving Linear Equation

Multiply 0 and 2 to get 0.

$$3x-4+0x=15+12x+21$$

Anything times zero gives zero.

$$3x-4+0=15+12x+21$$

Add -4 and 0 to get -4.

$$3x-4=15+12x+21$$

Add 15 and 21 to get 36.

$$3x-4=36+12x$$

Subtract 12x from both sides.

$$3x-4-12x=36$$

Combine 3x and -12x to get -9x.

$$-9x-4=36$$

Add 4 to both sides.

$$-9x=36+4$$

Add 36 and 4 to get 40.

$$-9x=40$$

Divide both sides by -9.

$$x=\frac{40}{-9}$$

Fraction \frac{40}{-9} can be rewritten as -\frac{40}{9} by extracting the negative sign.

$$x=-\frac{40}{9}$$