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3x-4\sqrt{3}x=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
\left(3-4\sqrt{3}\right)x=-3
Combine all terms containing x.
\frac{\left(3-4\sqrt{3}\right)x}{3-4\sqrt{3}}=-\frac{3}{3-4\sqrt{3}}
Divide both sides by 3-4\sqrt{3}.
x=-\frac{3}{3-4\sqrt{3}}
Dividing by 3-4\sqrt{3} undoes the multiplication by 3-4\sqrt{3}.
x=\frac{4\sqrt{3}+3}{13}
Divide -3 by 3-4\sqrt{3}.