Solve 3x-4left(y-2right)=2

$$3x-4 \left( y-2 \right) = 2$$

Solve for x

$$x=\frac{4y}{3}-2$$

Steps for Solving Linear Equation

Use the distributive property to multiply -4 by y-2.

$$3x-4y+8=2$$

Add 4y to both sides.

$$3x+8=2+4y$$

Subtract 8 from both sides.

$$3x=2+4y-8$$

Subtract 8 from 2 to get -6.

$$3x=-6+4y$$

The equation is in standard form.

$$3x=4y-6$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{4y-6}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{4y-6}{3}$$

Divide -6+4y by 3.

$$x=\frac{4y}{3}-2$$

Solve for y

$$y=\frac{3\left(x+2\right)}{4}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -4 by y-2.

$$3x-4y+8=2$$

Subtract 3x from both sides.

$$-4y+8=2-3x$$

Subtract 8 from both sides.

$$-4y=2-3x-8$$

Subtract 8 from 2 to get -6.

$$-4y=-6-3x$$

The equation is in standard form.

$$-4y=-3x-6$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{-3x-6}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{-3x-6}{-4}$$

Divide -6-3x by -4.

$$y=\frac{3x}{4}+\frac{3}{2}$$