Solve for x
x = \frac{1}{3} = 0.3333333333333333
Solve for y
y = -\frac{1}{3} = -0.3333333333333333
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3x=1+3y
Add 3y to both sides.
3x=3y+1
The equation is in standard form.
\frac{3x}{3}=\frac{3y+1}{3}
Divide both sides by 3.
x=\frac{3y+1}{3}
Dividing by 3 undoes the multiplication by 3.
x=y+\frac{1}{3}
Divide 1+3y by 3.
-3y=1-3x
Subtract 3x from both sides.
\frac{-3y}{-3}=\frac{1-3x}{-3}
Divide both sides by -3.
y=\frac{1-3x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=x-\frac{1}{3}
Divide 1-3x by -3.
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