Solve for x
x = -\frac{7}{3} = -2\frac{1}{3} = -2.3333333333333335
Solve for y
y = \frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335
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3x+7=3y
Add 3y to both sides. Anything plus zero gives itself.
3x=3y-7
Subtract 7 from both sides.
\frac{3x}{3}=\frac{3y-7}{3}
Divide both sides by 3.
x=\frac{3y-7}{3}
Dividing by 3 undoes the multiplication by 3.
x=y-\frac{7}{3}
Divide 3y-7 by 3.
-3y+7=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-3y=-3x-7
Subtract 7 from both sides.
\frac{-3y}{-3}=\frac{-3x-7}{-3}
Divide both sides by -3.
y=\frac{-3x-7}{-3}
Dividing by -3 undoes the multiplication by -3.
y=x+\frac{7}{3}
Divide -3x-7 by -3.
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Limits
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