Solve for x
x=\frac{2y+z+10}{3}
Solve for y
y=\frac{3x}{2}-\frac{z}{2}-5
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3x-z=10+2y
Add 2y to both sides.
3x=10+2y+z
Add z to both sides.
3x=2y+z+10
The equation is in standard form.
\frac{3x}{3}=\frac{2y+z+10}{3}
Divide both sides by 3.
x=\frac{2y+z+10}{3}
Dividing by 3 undoes the multiplication by 3.
-2y-z=10-3x
Subtract 3x from both sides.
-2y=10-3x+z
Add z to both sides.
-2y=10+z-3x
The equation is in standard form.
\frac{-2y}{-2}=\frac{10+z-3x}{-2}
Divide both sides by -2.
y=\frac{10+z-3x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x}{2}-\frac{z}{2}-5
Divide 10-3x+z by -2.
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