Solve 3x-2y-3/2=0

$$3x-2y- \frac{ 3 }{ 2 } =0$$

Solve for x

$$x=\frac{2y}{3}+\frac{1}{2}$$

Steps for Solving Linear Equation

Add 2y to both sides. Anything plus zero gives itself.

$$3x-\frac{3}{2}=2y$$

Add \frac{3}{2} to both sides.

$$3x=2y+\frac{3}{2}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{2y+\frac{3}{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{2y+\frac{3}{2}}{3}$$

Divide 2y+\frac{3}{2} by 3.

$$x=\frac{2y}{3}+\frac{1}{2}$$

Solve for y

$$y=\frac{3x}{2}-\frac{3}{4}$$

Steps for Solving Linear Equation

Subtract 3x from both sides. Anything subtracted from zero gives its negation.

$$-2y-\frac{3}{2}=-3x$$

Add \frac{3}{2} to both sides.

$$-2y=-3x+\frac{3}{2}$$

The equation is in standard form.

$$-2y=\frac{3}{2}-3x$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{\frac{3}{2}-3x}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{\frac{3}{2}-3x}{-2}$$

Divide -3x+\frac{3}{2} by -2.

$$y=\frac{3x}{2}-\frac{3}{4}$$