Solve for x
x=\frac{2\left(y-9\right)}{3}
Solve for y
y=\frac{3\left(x+6\right)}{2}
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3x=-18+2y
Add 2y to both sides.
3x=2y-18
The equation is in standard form.
\frac{3x}{3}=\frac{2y-18}{3}
Divide both sides by 3.
x=\frac{2y-18}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{2y}{3}-6
Divide -18+2y by 3.
-2y=-18-3x
Subtract 3x from both sides.
-2y=-3x-18
The equation is in standard form.
\frac{-2y}{-2}=\frac{-3x-18}{-2}
Divide both sides by -2.
y=\frac{-3x-18}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x}{2}+9
Divide -18-3x by -2.
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Limits
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