Solve 3x-20=160-2y^2

$$3x-20=160-2 { y }^{ 2 }$$

Solve for x

$$x=-\frac{2y^{2}}{3}+60$$

Steps for Solving Linear Equation

Add 20 to both sides.

$$3x=160-2y^{2}+20$$

Add 160 and 20 to get 180.

$$3x=180-2y^{2}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{180-2y^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{180-2y^{2}}{3}$$

Divide 180-2y^{2} by 3.

$$x=-\frac{2y^{2}}{3}+60$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{360-6x}}{2}$$

$$y=\frac{\sqrt{360-6x}}{2}$$

Solve for y

$$y=\frac{\sqrt{360-6x}}{2}$$

$$y=-\frac{\sqrt{360-6x}}{2}\text{, }x\leq 60$$