Solve 3x-19+459-595+19-69=*-26*25div259*2=758

$$3x-19+459-595+19-69= \times -26 \times 25 \div 259 \times 2=758$$

Evaluate

$$3x-205$$

Solution Steps

Add -19 and 459 to get 440.

$$3x+440-595+19-69$$

Subtract 595 from 440 to get -155.

$$3x-155+19-69$$

Add -155 and 19 to get -136.

$$3x-136-69$$

Subtract 69 from -136 to get -205.

$$3x-205$$

Differentiate w.r.t. x

$$3$$

Steps Using Derivative Rule for Sum

Add -19 and 459 to get 440.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+440-595+19-69)$$

Subtract 595 from 440 to get -155.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-155+19-69)$$

Add -155 and 19 to get -136.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-136-69)$$

Subtract 69 from -136 to get -205.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-205)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$3x^{1-1}$$

Subtract 1 from 1.

$$3x^{0}$$

For any term t except 0, t^{0}=1.

$$3\times 1$$

For any term t, t\times 1=t and 1t=t.

$$3$$