Solve 3x(-x+3)+4x=-3x^2+2x-1

$$3x(-x+3)+4x=-3 { x }^{ 2 } +2x-1$$

Solve for x

$$x=-\frac{1}{11}\approx -0.090909091$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3x by -x+3.

$$3x\left(-x\right)+9x+4x=-3x^{2}+2x-1$$

Combine 9x and 4x to get 13x.

$$3x\left(-x\right)+13x=-3x^{2}+2x-1$$

Add 3x^{2} to both sides.

$$3x\left(-x\right)+13x+3x^{2}=2x-1$$

Subtract 2x from both sides.

$$3x\left(-x\right)+13x+3x^{2}-2x=-1$$

Combine 13x and -2x to get 11x.

$$3x\left(-x\right)+11x+3x^{2}=-1$$

Multiply 3 and -1 to get -3.

$$-3xx+11x+3x^{2}=-1$$

Multiply x and x to get x^{2}.

$$-3x^{2}+11x+3x^{2}=-1$$

Combine -3x^{2} and 3x^{2} to get 0.

$$11x=-1$$

Divide both sides by 11.

$$x=\frac{-1}{11}$$

Fraction \frac{-1}{11} can be rewritten as -\frac{1}{11} by extracting the negative sign.

$$x=-\frac{1}{11}$$