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Solve for x
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3x=y+z
The equation is in standard form.
\frac{3x}{3}=\frac{y+z}{3}
Divide both sides by 3.
x=\frac{y+z}{3}
Dividing by 3 undoes the multiplication by 3.
y+z=3x
Swap sides so that all variable terms are on the left hand side.
y=3x-z
Subtract z from both sides.