Solve for x
x=3z-\frac{4}{3}
Solve for z
z=\frac{x}{3}+\frac{4}{9}
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3x=9z-4
The equation is in standard form.
\frac{3x}{3}=\frac{9z-4}{3}
Divide both sides by 3.
x=\frac{9z-4}{3}
Dividing by 3 undoes the multiplication by 3.
x=3z-\frac{4}{3}
Divide 9z-4 by 3.
9z-4=3x
Swap sides so that all variable terms are on the left hand side.
9z=3x+4
Add 4 to both sides.
\frac{9z}{9}=\frac{3x+4}{9}
Divide both sides by 9.
z=\frac{3x+4}{9}
Dividing by 9 undoes the multiplication by 9.
z=\frac{x}{3}+\frac{4}{9}
Divide 3x+4 by 9.
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